-16x^2+25x+260=0

Solution for -16x^2+25x+260=0 equation:

-16x^2+25x+260=0

a = -16; b = 25; c = +260;
Δ = b2-4ac
Δ = 252-4·(-16)·260
Δ = 17265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{17265}}{2*-16}=\frac{-25-\sqrt{17265}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{17265}}{2*-16}=\frac{-25+\sqrt{17265}}{-32}
$